5x^2-98x-2205=0

Solution for 5x^2-98x-2205=0 equation:

5x^2-98x-2205=0

a = 5; b = -98; c = -2205;
Δ = b2-4ac
Δ = -982-4·5·(-2205)
Δ = 53704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{53704}=\sqrt{196*274}=\sqrt{196}*\sqrt{274}=14\sqrt{274}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14\sqrt{274}}{2*5}=\frac{98-14\sqrt{274}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14\sqrt{274}}{2*5}=\frac{98+14\sqrt{274}}{10}
$